sqrt(2)-1 = 1/(sqrt(2)+1)
Can someone show me how this is possible?
Note that $\displaystyle \sqrt{2}-1=\left(\sqrt{2}-1\right)\cdot1=\left(\sqrt{2}-1\right)\frac{\sqrt{2}+1}{\sqrt{2}+1}=\frac{\left( \sqrt{2}-1\right)\left(\sqrt{2}+1\right)}{\sqrt{2}+1}=\frac {2-1}{\sqrt{2}+1}$ $\displaystyle =\frac{1}{\sqrt{2}+1}$
Does this make sense?
EDIT: Grr...I'm too slow today... XD