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Math Help - rearranging log function

  1. #1
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    Post rearranging log function

    Hi all..

    I wanted to know how to rearrange the following to get S as subject, just bit confused on what to do with the Clog mulitplying the S

    K = logT + ClogS

    Thank you
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  2. #2
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    Quote Originally Posted by dadon View Post
    Hi all..

    I wanted to know how to rearrange the following to get S as subject, just bit confused on what to do with the Clog mulitplying the S

    K = logT + ClogS

    Thank you
    I assume that \log means \log_{10}.

    If so:

    K=\log(T) +C \cdot \log(S)=\log(T \cdot S^C)

    Now use the base 10:

    10^K= T \cdot S^C ~\implies~\boxed{S=\sqrt[C]{\dfrac{10^K}{T}}}
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  3. #3
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    Quote Originally Posted by earboth View Post
    I assume that \log means \log_{10}.

    If so:

    K=\log(T) +C \cdot \log(S)=\log(T \cdot S^C)

    Now use the base 10:

    10^K= T \cdot S^C ~\implies~\boxed{S=\sqrt[C]{\dfrac{10^K}{T}}}
    Thanks for the help. Nicely explained
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  4. #4
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    Quote Originally Posted by dadon View Post
    I wanted to know how to rearrange the following to get S as subject, just bit confused on what to do with the Clog mulitplying the S

    K = logT + ClogS
    Um.... "Clog" is not "multiplying the S"!

    The "ClogS" is the product of the variable "C" and the logarithmic function of S; that is, "ClogS" means C\times\log(S), not Clog\times S

    To learn about logarithms, try some online lessons.
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