Thread: rearranging log function

1. rearranging log function

Hi all..

I wanted to know how to rearrange the following to get S as subject, just bit confused on what to do with the Clog mulitplying the S

K = logT + ClogS

Thank you

2. Originally Posted by dadon
Hi all..

I wanted to know how to rearrange the following to get S as subject, just bit confused on what to do with the Clog mulitplying the S

K = logT + ClogS

Thank you
I assume that $\log$ means $\log_{10}$.

If so:

$K=\log(T) +C \cdot \log(S)=\log(T \cdot S^C)$

Now use the base 10:

$10^K= T \cdot S^C ~\implies~\boxed{S=\sqrt[C]{\dfrac{10^K}{T}}}$

3. Originally Posted by earboth
I assume that $\log$ means $\log_{10}$.

If so:

$K=\log(T) +C \cdot \log(S)=\log(T \cdot S^C)$

Now use the base 10:

$10^K= T \cdot S^C ~\implies~\boxed{S=\sqrt[C]{\dfrac{10^K}{T}}}$
Thanks for the help. Nicely explained

4. Originally Posted by dadon
I wanted to know how to rearrange the following to get S as subject, just bit confused on what to do with the Clog mulitplying the S

K = logT + ClogS
Um.... "Clog" is not "multiplying the S"!

The "ClogS" is the product of the variable "C" and the logarithmic function of S; that is, "ClogS" means $C\times\log(S)$, not $Clog\times S$

To learn about logarithms, try some online lessons.