Buenas noches. Well lastlion, these are not algebra questions, but rather calculus. Basic differentiation skills are required to work these questions.

When you differentiate an equation/function, you can find its slope at any particular point

Q1:

$\displaystyle Y = 4 + 3X^2$

$\displaystyle \frac{dY}{dX}=6X$

$\displaystyle Let X=3$

$\displaystyle Slope=18$

Q3:

$\displaystyle Y = 6X$

$\displaystyle \frac{dY}{dX}=6$

$\displaystyle Slope=6$

Q2:

$\displaystyle Y = 3X = 6X^3$

Needs clarification.

Point 1:If $\displaystyle Y=3X$, then the slope is $\displaystyle 3$, and if $\displaystyle Y=6X^3$, the slope is $\displaystyle 162$. Neither of which is your answer

Point 2: This is in the form of an equation to be solved for $\displaystyle X$,in which case the solution would be $\displaystyle X=\pm\sqrt{\frac{1}{2}}$.

I am very confused...

First time using a smiley in a post

(2nd time now.)

Edit: It seems I'm a bit too late, Chris L T521 is on the scene