Thread: quadradics with complex

Hi, this is my last help for today. I want to thank Hacker for being so helpful.
I also want to apologize to Hacker for double posting, I won't do it again.

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Give f(x) = x^2+6x+13 in factored form, and show that when you multiply the factors together you get f(x) in standard form.

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Help please =[

This quadratic has complex roots.

What two values when added equal 6 and when multiplied equal 13

There are no reals that fit this criteria.

(3-2i) and (3+2i)

(3-2i)+(3+2i)=6

(3-2i)(3+2i)=13