Having trouble getting started on a few of these. 1. 5^(x-10) = 125^x 2. (3/4) log x ^(3/4) + 9 = 0 thanks again!
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Hello.. 1) 125^x=5^(3x) => x-10=3x => x=-5 2) 3/4 * log x ^(3/4) + 9 = 0 => 3/4*3/4 * log x = -9 => 1/16 * log x = -1 => log x = -16 if log = ln => x=e^(-16)
Hello, Hapa! We have: . Equate exponents: . We have: . . . . . . . Edit: Too slow ... again!
soroban, how do you do to write the equations so beautiful ?
he used mathtype to write it like that and here is another way to solve: 5^(x-10)= 125^x 5^(x-10)= 5^(3x) Take "log" of both sides: (x-10)log5= (3x)log5 dividing both sides by log5: x-10= 3x x= -5
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