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Math Help - Bah 3 Questions 1 Hour til School :s

  1. #1
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    Bah 3 Questions 1 Hour til School :s

    oops
    Last edited by Naif; December 14th 2006 at 03:27 AM. Reason: Sorry read wrong, Sections wrong
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by Naif View Post
    (1/x - 2) = (3/x + 2) - (6x/x - 4)
    (3/x + 2) - (6x/x - 4) = (3/x + 2) - (6/x - 4)

    ...............................= (3/x-6/x) + (2-4) = -3/x -2

    So if

    (1/x - 2) = (3/x + 2) - (6x/x - 4),

    then:

    1/x-2=-3/x-2,

    1=-3

    which is a contradiction.

    So your question means something else, so lets put some brackets in:

    So show that:

    1/(x - 2) = 3/(x + 2) - 6x/(x - 4)

    the righthand side is:

    3/(x + 2) - 6x/(x - 4) = [3(x-2) - 6x]/(x^2-4)

    (this is since (x^2-4)=(x-2)(x+2))

    so:

    3/(x + 2) - 6x/(x - 4) = [-6 - 3x]/(x^2-4)=-3(x+2)/(x^2-4)=-3/(x-2)

    So its still not true


    RonL
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