Find the direction in which a straight line must be drawn through the point (-1,2) so that it's point of intersection with the line x + y = 4 may be at a distance of 3 units from this point. Oh yeah I used graph , I'm getting a line parallel line to x- axis... How o solve this analyticaly...?
Can't solve this question du to too many unknown variables.... besides I dont think they are asking for perpendicular distance, be cause when I checked with the formula d = abs ( Ax1 + By1 + C)/SQRT(A^2 B^2)'whrer x1 = -1 , y1 = 2 ...
Q2 The hypotenuse of a right trianlge has its ends at the points (1,3) and (-4,1). Find te equaion of the legs ( perpendicular sides ) of this triangle.
I don't think there is a solution for both the legs because I feel that the hypotenuse can be considered asa diamter of a cirlce , and it subtends 90 degree at infinite points on it's circumference, but my textbook says the anser is x=1 , y=1 ... shouldnt we get a quadratic equation ??