Thread: More logarithmic help

I have to graph y=6^x and its inverse on the same axes.

Would it just be y=log6 x for the inverse?

After that it says the graph of the inverse can be used to solve for the exponent of the original function. Explain how the graph can be used to solve for 36 = 6^x

Then finally using the equation of the inverse function approximate a solution for the original function y = 6^x for the following values:
y=6
y=1
y=88
y=15

I'm a little confused on how to do this, any guidance would be great.

Originally Posted by olen12

I have to graph y=6^x and its inverse on the same axes.

Would it just be y=log6 x for the inverse?

Yes, that is true.

After that it says the graph of the inverse can be used to solve for the exponent of the original function. Explain how the graph can be used to solve for 36 = 6^x

The inverse is . Find 36 on the x axis, go up to the graph of then go horizontally to the y axis to find the y coordinate of the point.

Then finally using the equation of the inverse function approximate a solution for the original function y = 6^x for the following values:
y=6
y=1
y=88
y=15

I'm a little confused on how to do this, any guidance would be great.

Look up x= 6, x= 1, x= 88, x= 15 on the x-axis, go up from each to the graph , and from that point horizontally to the y-axis.