# Thread: Solving tricky simultaneous equations

1. ## Solving tricky simultaneous equations

Well tricky for me anyway... (non- maths guy)
Is it possible to solve these simultaneously & if so pretty please show me how (even though they simplify to the same equation)

7B+1+(C-1)(6B+1)=41

7C+1+(B-1)(6C+1)=41

I mean is it possible to get an answer for C&B in positive integers...

Thanks again guys, really appreciate your help!

2. Using just your first equation

$\displaystyle 7B+1+(C-1)(6B+1)=41$

Expand the brackets

$\displaystyle 7B+1+(6BC+C-6B-1)=41$

Remove the brackets

$\displaystyle 7B+1+6BC+C-6B-1=41$

Group like terms together

$\displaystyle B+6BC+C=41$

Factor B out of the first 2 terms

$\displaystyle B(1+6C)+C=41$

Take C from Both sides

$\displaystyle B(1+6C)=41-C$

Divde (1+6C) through both sides

$\displaystyle B=\frac{41-C}{1+6C}$

Now sub this into the 2nd equation for B.

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# tricky silmutaneous questio

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