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Math Help - Solving tricky simultaneous equations

  1. #1
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    Solving tricky simultaneous equations

    Well tricky for me anyway... (non- maths guy)
    Is it possible to solve these simultaneously & if so pretty please show me how (even though they simplify to the same equation)

    7B+1+(C-1)(6B+1)=41

    7C+1+(B-1)(6C+1)=41

    I mean is it possible to get an answer for C&B in positive integers...

    Thanks again guys, really appreciate your help!
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  2. #2
    Master Of Puppets
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    Using just your first equation

    7B+1+(C-1)(6B+1)=41

    Expand the brackets

    7B+1+(6BC+C-6B-1)=41

    Remove the brackets

    7B+1+6BC+C-6B-1=41

    Group like terms together

    B+6BC+C=41

    Factor B out of the first 2 terms

    B(1+6C)+C=41

    Take C from Both sides

    B(1+6C)=41-C

    Divde (1+6C) through both sides

    B=\frac{41-C}{1+6C}

    Now sub this into the 2nd equation for B.
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