# Math Help - check this please

can someone tell me if this is right
simplify

3x
x

minus

x
x+1

2x^2+4x
x(x+1)

2. $
\frac{3x}{x}-\frac{x}{x+1}=
$

multiplying by $(x+1)$ for the left fraction and $(x)$ for the right fraction gives

$
\frac{3x(x+1)-x*(x)}{x(x+1)}=
$

simplifying the numerator

$\frac{3x^2+3x-x^2}{x(x+1)}=$

more simplifying

$\frac{2x^2+3x}{x(x+1)}=$

factoring $x$ out of the numerator and canceling it with the $x$ in the denominator leaves

$
\frac{2x+3}{x+1}
$