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Math Help - reduction of a relationship to a linear law

  1. #1
    Newbie scouser's Avatar
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    reduction of a relationship to a linear law

    y= k(x+1) to the power of n
    find approximate values for k and n given that

    x 4 8 15
    y 4.45 4.60 4.8
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  2. #2
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    Grandad's Avatar
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    Hello scouser
    Quote Originally Posted by scouser View Post
    y= k(x+1) to the power of n
    find approximate values for k and n given that

    x 4 8 15
    y 4.45 4.60 4.8
    Take logs of both sides:

    \log y = \log\Big(k(x+1)^n\Big)

    = \log k +n\log(x+1)

    Plot the graph of \log y against \log(x+1), using the three pairs of values you're given. Draw the best straight line and read off the gradient and intercept.

    Gradient = n \approx 0.065

    Intercept = \log k, which gives k \approx 4

    Grandad
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