of a sphere witha center (1,4,-3) and tangent to the xz plane
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Originally Posted by tiga killa of a sphere witha center (1,4,-3) and tangent to the xz plane r is the distance from the point (1,4,-3) to the xz plane ... which I leave for you to figure out.
Hello, tiga killa! Write the equaton of a sphere with center (1,4,-3) and tangent to the xz-plane We have the center . . . we just need the radius, right? Can you visualize the sphere? . . If it is tangent to the xz-plane, the radius is 4. Therefore: .
Hello, You have just to find the radius of this sphere. It corresponds of the abscissa since it has to be tangent to . Hence and thus the equation of the sphere is Edit : What I called is the plan , maybe the sphere is tangent to ?
Last edited by Infophile; May 5th 2009 at 01:55 PM.
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