Originally Posted by
duckduckgoose33 The problems is:
One factor of x^3 + 2x^2 - 23x - 60 is (x=4). Find the remianing factors.
I tried to group them and factor but the second binomial wouldn't factor.
They tell you x=4 is a solution,
But that is not true!
Perhaps you mean x=-4
That means
(x-(-4))=(x+4)
Is a factor.
Thus, use long division,
Code:
x^3 + 2x^2 - 23x - 60 : x + 4=x^2 - 2x-15
x^3 + 4x^2
-------------
-2x^2 - 23x - 60
-2x^2 - 8x
------------
-15x - 60
-15x - 60
----------
0
Now we need to factor,
x^2-2x-15
Which factors as,
(x-5)(x+3)
Thus, the full factorization is,
(x-5)(x+3)(x+4)