:confused: I've been stuck on this inequality:

[(x-9)/(x^3)1/(x+9)]<0

The solution of this inequality consists one or more of the following intervals:

(-infinity, A), (A,B), (B,C), and (C, infinity) where A<B<C

Find A, B and C

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- Sep 11th 2005, 11:35 AMClallyraplease help
:confused: I've been stuck on this inequality:

[(x-9)/(x^3)1/(x+9)]<0

The solution of this inequality consists one or more of the following intervals:

(-infinity, A), (A,B), (B,C), and (C, infinity) where A<B<C

Find A, B and C - Sep 11th 2005, 01:36 PMMath Help
[(x-9)/(x^3)1/(x+9)]<0

Here is a start:

Find when the equality equals 0

Looking at the equation there are three ways you could get 0 or undefined:

when (x-9) = 0, x=9

when (x^3)1 = 0, x=0

and when (x+9) = 0, x=-9