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Math Help - [SOLVED] Simplification of Algeraic Fractions

  1. #1
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    [SOLVED] Simplification of Algeraic Fractions

    Q. Simplify the following:
    \frac {3x^2y - 6xy}{2x^2y - 4xy^2}

    i've got up to

    \frac {3xy(x - 2)}{2xy(x - 2y)}

    i tried simplifying it further but i just end up getting the wrong answer, which is \frac{3}{2y}
    thanks
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  2. #2
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    The answer you've been given is wrong. The only way for the expression to simplify that way would be for the original expression to change the power on the first of the "y" terms in the denominator:

    . . . . . \frac{3x^2y\, -\, 6xy}{2x^2y^2\, -\, 4xy^2}

    . . . . . \frac{3xy(x\, -\, 2)}{2xy^2(x\, -\, 2)}

    . . . . . \frac{3xy}{2xy^2}

    . . . . . \frac{3}{2y}

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  3. #3
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    Quote Originally Posted by stapel View Post
    The answer you've been given is wrong. The only way for the expression to simplify that way would be for the original expression to change the power on the first of the "y" terms in the denominator:

    . . . . . \frac{3x^2y\, -\, 6xy}{2x^2y^2\, -\, 4xy^2}

    . . . . . \frac{3xy(x\, -\, 2)}{2xy^2(x\, -\, 2)}

    . . . . . \frac{3xy}{2xy^2}

    . . . . . \frac{3}{2y}

    ... but is it still possible to simplify \frac {3xy(x - 2)}{2xy(x - 2y)} further? like maybe \frac {3(x - 2)}{2(x - 2y)}
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  4. #4
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    Quote Originally Posted by waven View Post
    ... but is it still possible to simplify \frac {3xy(x - 2)}{2xy(x - 2y)} further? like maybe \frac {3(x - 2)}{2(x - 2y)}
    Yes, that's correct - xy does cancel
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