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- May 4th 2009, 12:17 AMAquafinaColours
on another thread now

- May 4th 2009, 01:26 AMbebrave
- May 4th 2009, 03:13 AMAquafina
how does this help me? sorry i didnt understand that

- May 4th 2009, 03:44 AMbebrave
Solution

Look at two adjacent rows, A and B. Suppose row A has

• r red dots beside red dots in B,

• b blue dots beside blue dots in B,

• u red dots beside blue dots in B and

• v blue dots beside red dots in B.

Then there are r red and b blue segments joining elements of A to elements of B.

A has r + u red dots and b + v blue dots, while B has r + v red dots and b + u blue dots. We get

that r+u = b+v and r+v = b+u. Rearranging, we get r−b = v −u = −(v −u); in other words,

r − b = 0, or r = b.

Hence between adjacent rows, the number of red segments equals the number of blue segments.

The same is true for adjacent columns. Thus the total number of blue segments is equal to the

total number of red segments, as desired.

solution does not belong to me..I saw already in forum...i like it so I added to my archive..Thanks to the person who solved... - May 4th 2009, 03:54 AMAquafina
doesnt it look like this?

- May 4th 2009, 04:00 AMbebrave
yeah

shape like this

blue---blue,red---red

red---red,blue---blue

blue---blue,red---red

red---red,blue---blue - May 4th 2009, 04:03 AMAquafina
but in this one each time the colour on a row is alternate to the previous one, in yours they are at random order?