2^y+1 = 3x 5^y
So you are supposed to solve the equation, which is as follows:
. . . . .$\displaystyle 2^{y+1}\, =\, 3\left(5^y\right)$
A good start for solving this exponential equation would probably be to take the log of either side:
. . . . .$\displaystyle \ln(2^{y+1})\, =\, \ln(3(5^y))$
Apply a log rule to split apart the right-hand side:
. . . . .$\displaystyle \ln(2^{y+1})\, =\, \ln(3)\, +\, \ln(5^y)$
Use the definition of logs to simplify as:
. . . . .$\displaystyle (y\, +\, 1)\ln(2)\, =\, \ln(3)\, +\, (y)\ln(5)$
Then solve this linear equation for "y=".
In future, please show the work you've done.
In this case, I showed the hard part on the assumption that you'd already studied the easy part. (It's highly unusual to teach how to work with logarithms before having taught how to solve linear equations.) To learn how to do the remaining step, please try here.