• May 2nd 2009, 04:29 PM
chrozer
Express the area of the shaded triangle in terms of "y".

I have attached a picture of the problem. As you can see, I have already tried to solve the problem, but to no avail. I cannot figure it out at all. Any ideas?
• May 2nd 2009, 05:21 PM
Plato
The answer is to be in terms of y.
Every point ont your line is \$\displaystyle (4-2y,y)\$
The width is \$\displaystyle 4-2y\$ and the length is \$\displaystyle y\$.
What is the area?
• May 2nd 2009, 05:37 PM
chrozer
Quote:

Originally Posted by Plato
The answer is to be in terms of y.
Every point ont your line is \$\displaystyle (4-2y,y)\$
The width is \$\displaystyle 4-2y\$ and the length is \$\displaystyle y\$.
What is the area?

So the width is \$\displaystyle 4y - 2y^2\$? ok..I see it now.
• May 2nd 2009, 05:52 PM
Plato
Quote:

Originally Posted by chrozer
So the width is \$\displaystyle 4y - 2y^2\$? ok..I see it now.

No the area is \$\displaystyle 4y - 2y^2\$.
• May 2nd 2009, 06:43 PM
chrozer
Quote:

Originally Posted by Plato
No the area is \$\displaystyle 4y - 2y^2\$.

Ok yeah...sorry that's what I meant. Thanks alot.