Hi
therefore you get
Ok. Here is my problem.
And my aproach
I'm having some trouble to solve for these signs...mmm...The book I'm using has the answers to odd problems only. This is an even one. But anyway, I want to have it right. The istruction says "Simplify as much as possible" And I've got the feeling this can be worked further. Any idea?
PS: I thought about multiplicating by -1, but then It would be the same as the numerator'd turn into negatives.
How many times will 1 go into -1 (-1 times right?)
How many times will 5 go into -5 (-1 times right?)
how many times will 10,000 go into -10000 (-1 times right?)
So, how many times will a go into -a
You guessed it -1 TIMES!
So the two a's cacel to become -1! Got It?
according to what running-gag said and following the approach I started using, the development should follow as:
And there it was...!!! Ops...wait...wait...wait...What if this was this , which to me seem more correct. Then:
Now my question is which one is the right one:
a) or
b)
c) None. Then which______________________________?