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Math Help - Is that transformation possible ?

  1. #1
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    Is that transformation possible ?

    16x^2-8x+3=1+(ax+b)^2
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  2. #2
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    Quote Originally Posted by totalnewbie View Post
    16x^2-8x+3=1+(ax+b)^2

    If

    16x^2-8x+3=1+(ax+b)^2

    then

    16x^2-8x+3 = a^2 x^2+2 a b x+b^2+1


    so a=+/-4, ab=-8, so b=-/+2, and so b^2+1=4+1=5 != 3,
    which is a contradiction so there is no such real transformation.

    RonL
    Last edited by CaptainBlack; December 10th 2006 at 09:28 AM.
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