# Math Help - Is that transformation possible ?

1. ## Is that transformation possible ?

$16x^2-8x+3=1+(ax+b)^2$

2. Originally Posted by totalnewbie
$16x^2-8x+3=1+(ax+b)^2$

If

16x^2-8x+3=1+(ax+b)^2

then

16x^2-8x+3 = a^2 x^2+2 a b x+b^2+1

so a=+/-4, ab=-8, so b=-/+2, and so b^2+1=4+1=5 != 3,
which is a contradiction so there is no such real transformation.

RonL