# Thread: Mixing problem

1. ## Mixing problem

Q) Two containers of equal capacity are full of mixture of oil and water.In the first the ratio of oil to water is 4:7 and in the second it is 7:11. Now both the mixture are mixed in a big container.what is the resulting ratio of oil to water?

Thanks,
Ashish

2. Originally Posted by a69356
Q) Two containers of equal capacity are full of mixture of oil and water.In the first the ratio of oil to water is 4:7 and in the second it is 7:11. Now both the mixture are mixed in a big container.what is the resulting ratio of oil to water?

Thanks,
Ashish
Let V denote the volume of one container.

The the amount of oil is:

$\displaystyle \dfrac4{11} V + \dfrac7{18} V = \dfrac{149}{198} V$

and the amount of water is:

$\displaystyle \dfrac7{11} V + \dfrac{11}{18} V = \dfrac{247}{198} V$

Both amounts add up to 2 V.

Now calculate the new ratio.

3. lets say each container had capacity of x
volume of oil in first = 4x/(4+7) = 4x/11

Volume of water = 7x/11

In the second container

volume of water = 11x/18

volume of oil =7x/18

So total volume of oil = 7x/18 +4x/11

Volume of water = 11x/18 + 7x/11

So ratio = $\displaystyle \frac{Volume ~of ~oil}{Volume~ of ~water}$...go ahead

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# two containers of equal volume are fully filled

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