how do we do such problems? like... find the remainder when is divided by 79... or when is divided by 101... whats the method?
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Originally Posted by adhyeta how do we do such problems? like... find the remainder when is divided by 79... or when is divided by 101... whats the method? Easy way to solve such problem is like since 3^4=81 we have to take value greater than 79 hence (3^4)^9*3 = 3^37 3^4/79 = 81/79 leaves remainder 2 hence 2^9 *3 / 79 = 512*3 = 1536/79 will leaves a reminder 35 I hope it is Easy solution (think of binomial expansion)
Originally Posted by ADARSH hence (3^4)^9*3 = 3^37 dint get this
Originally Posted by adhyeta dint get this
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