how do we do such problems? :confused:
like...
find the remainder whenis divided by 79...
or whenis divided by 101...
whats the method?
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how do we do such problems? :confused:
like...
find the remainder when
or when
whats the method?
Quote:
Originally Posted by adhyeta
how do we do such problems? :confused:
like...
find the remainder when
or when
whats the method?
Easy way to solve such problem is like
since 3^4=81 we have to take value greater than 79 hence (3^4)^9*3 = 3^37
3^4/79 = 81/79 leaves remainder 2 hence 2^9 *3 / 79 = 512*3 = 1536/79 will leaves a reminder 35
I hope it is Easy solution (think of binomial expansion)
dint get thisQuote:
Originally Posted by ADARSH
Quote:
Originally Posted by adhyeta