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Thread: Complex numbers

  1. #1
    Super Member
    Feb 2008

    Complex numbers

    I'm in a number systems class, which has us prove things we already know from scratch.

    I need to prove that Multiplication on complex numbers are associative.

    We have defined complex numbers to be ordered pairs and definition of multiplication and addition of complex numbers is as follows:

    (x1, y1)(x2, y2) = (x1x2 - y1y2, y1x2 + x1y2) and

    (x1, y1) + (x2, y2) = (x1 + x2, y1 + y2)

    I must show [(x,y)(z,w)] (a,b) = (x,y) [(z,w)(a,b)]

    Any advice?
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  2. #2
    MHF Contributor red_dog's Avatar
    Jun 2007
    Medgidia, Romania
    $\displaystyle [(x,y)(z,w)](a,b)=(xz-yw,xw+yz)(a,b)=$

    $\displaystyle =(axz-ayw-bxw-byz,bxz-byw+axw+ayz)$ (1)

    $\displaystyle (x,y)[(z,w)(a,b)]=(x,y)(az-bw,bz+aw)=$

    $\displaystyle =(axz-bxw-byz-ayw,bxz+axw+ayz-byw)$ (2)

    From (1) and (2) we have equality.
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