# mixture problem?

• Apr 30th 2009, 03:55 AM
a69356
mixture problem?
Q) A merchant purchased 2 quality of pulses at the rate of Rs 200 and Rs 260 per quintal. In 52 quintals of 2nd quality, how much pulse of 1st quality should be mixed so that by selling the resulting mixture at Rs 300 per quintal,he gains a profit of 25% ?

Thanks,
Ashish
• Apr 30th 2009, 04:08 AM
e^(i*pi)
Quote:

Originally Posted by a69356
Q) A merchant purchased 2 quality of pulses at the rate of Rs 200 and Rs 260 per quintal. In 52 quintals of 2nd quality, how much pulse of 1st quality should be mixed so that by selling the resulting mixture at Rs 300 per quintal,he gains a profit of 25% ?

Thanks,
Ashish

Let the high quality pulse be x and the low quality one y. I will also use a basis of one quintal (whatever one is XD)

x = 260, y = 200

$\displaystyle \frac{52y + ax}{52+a} = \frac{300}{1-0.25}$

Since we know x and y it simplifies to:

$\displaystyle \frac{10400 + 260a}{52+a} = 240$

Solve for a which will be the number of high quality needed.
• Apr 30th 2009, 07:39 AM
HallsofIvy
"Pulses", by the way, are peas and beans, including soy beans and lentils, some of the most healthy of foods.