Find the set of values of k for which any solution of the inequality $\displaystyle \frac{\log_{2}(x^2 - 5x + 6)}{\log_{2}(2x)}< 1$ is also a solution of the inequality $\displaystyle x^2 - 7kx + 2k - 6\leq0$

Printable View

- Apr 29th 2009, 05:19 AMfardeen_genLogarithmic inequality?
Find the set of values of k for which any solution of the inequality $\displaystyle \frac{\log_{2}(x^2 - 5x + 6)}{\log_{2}(2x)}< 1$ is also a solution of the inequality $\displaystyle x^2 - 7kx + 2k - 6\leq0$

- Apr 29th 2009, 08:23 AMsteiner
try using the change of base formula to solve for values that make the inequality an equivalence.

and then relate those values to the second equation