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Math Help - Another linear system

  1. #1
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    Another linear system

    y=2x+4
    10x-5y=-20

    i know using the substitution method plays out like so...
    10x-5(2x+4)=-20
    10x-10x-20=-20
    10x-10x=0
    0=0

    I have to express the answer in interval notation....how would I do that, and since the answer is 0=0 is their a value for x and y at all
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  2. #2
    A riddle wrapped in an enigma
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    Quote Originally Posted by nmound View Post
    y=2x+4
    10x-5y=-20

    i know using the substitution method plays out like so...
    10x-5(2x+4)=-20
    10x-10x-20=-20
    10x-10x=0
    0=0

    I have to express the answer in interval notation....how would I do that, and since the answer is 0=0 is their a value for x and y at all
    Hi nmound,

    The second equation is a multiple of the first equation making them the same line. There is an infinite number of solutions. We call this system "consistent and dependent".

    Solution: (- \infty, + \infty)
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