Another linear system

y=2x+4
10x-5y=-20

i know using the substitution method plays out like so...
10x-5(2x+4)=-20
10x-10x-20=-20
10x-10x=0
0=0

I have to express the answer in interval notation....how would I do that, and since the answer is 0=0 is their a value for x and y at all

Quote:

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Originally Posted by nmound

y=2x+4
10x-5y=-20

i know using the substitution method plays out like so...
10x-5(2x+4)=-20
10x-10x-20=-20
10x-10x=0
0=0

I have to express the answer in interval notation....how would I do that, and since the answer is 0=0 is their a value for x and y at all

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Hi nmound,

The second equation is a multiple of the first equation making them the same line. There is an infinite number of solutions. We call this system "consistent and dependent".

Solution: