Totally suck at math (haven't done it since school and barely passed) but I need to use some simple algebra equations in some stuff I'm doing at the moment, I would appreciate any help.
My question is in the equation above I will know what number A is but I still don't know how to use it to find B.
Example when A is 16 B is 2 but I don't know how to figure it out, could you simplify this equation so that I can find B easily if I know A?
but I am assuming that you intended the second to be included in the denominator.
Since this is a cubic in there are at most 3 real solutions. Using the rational roots theorem, we may try and using some synthetic division we do indeed find this to be a solution. The cubic then factors as
Now we can simply use the quadratic formula. In the end, after factoring, we get
Therefore, the solutions to the original equation are
In case it isn't clear, and are always solutions, regardless of the value of The third solution is
Edit: Okay, it seems that the problem was as you had written it. In that case, all values of and satisfy the equation.
Thanks very much Reckoner, I must look like such a dunce asking such simple stuff
But I 'think' I finally figured out what I'm trying to ask, I think it is this equation below -
Only one or two values of B make it work I think.
Like if A is 16 only B=2 makes the equation make sense.
((6B-5) is meant to the denominator in the equation above)
So how do I simplify that so it is easy to find B if I know A