# Thread: How would I expand this bracket...

1. ## How would I expand this bracket...

I want to expand it, to get rid of the square root so i can later integrate it.. would the 'x' go to $x^\frac{1}{2}$ in the equation:

$(\sqrt{x}+1)^2$

2. Originally Posted by MikeNZ
I want to expand it, to get rid of the square root so i can later integrate it.. would the 'x' go to $x^\frac{1}{2}$ in the equation:

$(\sqrt{x}+1)^2$
If you expand this, you should get $\left(\sqrt{x}+1\right)^2=\left(\sqrt{x}\right)^2+ 2\left(\sqrt{x}\right)\left(1\right)+\left(1\right )^2=x+2\sqrt{x}+1$...

3. Originally Posted by MikeNZ
I want to expand it, to get rid of the square root so i can later integrate it.. would the 'x' go to $x^\frac{1}{2}$ in the equation:

$(\sqrt{x}+1)^2$
$(\sqrt{x}+1)^2 = (\sqrt{x}+1) (\sqrt{x}+1) = ....$

This expression will have a $\sqrt{x}$ in it, so when integrating it you should note that $\sqrt{x} = x^{1/2}$

4. Ahh ok, thanks you two!

5. Originally Posted by MikeNZ
I want to expand it, to get rid of the square root so i can later integrate it.. would the 'x' go to $x^\frac{1}{2}$ in the equation:

$(\sqrt{x}+1)^2$

Expansion is:

$(\sqrt{x}+1)^2 = x +2\sqrt{x}+1$

And yes

$\sqrt{x}=x^\frac{1}{2}$

6. I was a little late on the scene!

7. Originally Posted by pickslides
Expansion is:

$(\sqrt{x}+1)^2 = x +2\sqrt{x}+1$

And yes

$\sqrt{x}=x^\frac{1}{2}$

Ohhhh now i FULLY get it! Must of just had to read it over that one extra time. THANK YOU!