I want to expand it, to get rid of the square root so i can later integrate it.. would the 'x' go to $\displaystyle x^\frac{1}{2}$ in the equation:
$\displaystyle (\sqrt{x}+1)^2$
If you expand this, you should get $\displaystyle \left(\sqrt{x}+1\right)^2=\left(\sqrt{x}\right)^2+ 2\left(\sqrt{x}\right)\left(1\right)+\left(1\right )^2=x+2\sqrt{x}+1$...