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Math Help - y = x^2, vertex lies at (2,-3) open negative direction

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    y = x^2, vertex lies at (2,-3) open negative direction

    Beginning with the function y =x^2, which of the following shows the changes you would make so that the vertex lies at (2,− 3) and the parabola opens in a negative direction?


    my answer is y=-(x-2)^2 +3 am i correct?
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    Quote Originally Posted by peekybooyou View Post
    Beginning with the function y =x^2, which of the following shows the changes you would make so that the vertex lies at (2,− 3) and the parabola opens in a negative direction?


    my answer is y=-(x-2)^2 +3 am i correct?
    No.

    For any quadratic of the form y = a(x - h)^2 + k, it's vertex lies at (h, k). In other words, the x co-ordinate changes sign, but the y co-ordinate does not.

    So your answer should be y = -(x - 2)^2 \color{red}{-} 3.
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