# Math Help - y = x^2, vertex lies at (2,-3) open negative direction

1. ## y = x^2, vertex lies at (2,-3) open negative direction

Beginning with the function y =x^2, which of the following shows the changes you would make so that the vertex lies at (2,− 3) and the parabola opens in a negative direction?

my answer is y=-(x-2)^2 +3 am i correct?

2. Originally Posted by peekybooyou
Beginning with the function y =x^2, which of the following shows the changes you would make so that the vertex lies at (2,− 3) and the parabola opens in a negative direction?

my answer is y=-(x-2)^2 +3 am i correct?
No.

For any quadratic of the form $y = a(x - h)^2 + k$, it's vertex lies at $(h, k)$. In other words, the x co-ordinate changes sign, but the y co-ordinate does not.

So your answer should be $y = -(x - 2)^2 \color{red}{-} 3$.