It would be of some help if you could tell us what you want to calculate. If you are looking for the coordinates of the vertex then it isn't necessary to transform the given equation. You can pick up the coordinates as V(4, -2)

If the vertext has the coordinates then the general equation of a parabola opening right is:a simpler one that is throwing me off is

x = 2y^2 + 3

do i complete the square with this one as well? I know that since you have to get this into a the form "x = a(y - k)^2 + h" the 2 signifies that this parabola will open up to the right. but as far as figuring out the vertex from only 2 terms, i am getting mixed up.

Now transform the given equation into this form:

Therefore the vertex is at V(3, 0)

You are dealing with a parabola opening left:the last problem i have is the following

x = -y^2 + 4y - 3

since there is a negative sign in front of the y squared, do i go ahead and factor out a (-1), complete the square, and then plug into the quadratic formula? thanks again for everyone's help! hope you all had a wonderful weekend!

hapa

will yield: