If the vertext has the coordinates then the general equation of a parabola opening right is:a simpler one that is throwing me off is
x = 2y^2 + 3
do i complete the square with this one as well? I know that since you have to get this into a the form "x = a(y - k)^2 + h" the 2 signifies that this parabola will open up to the right. but as far as figuring out the vertex from only 2 terms, i am getting mixed up.
Now transform the given equation into this form:
Therefore the vertex is at V(3, 0)
You are dealing with a parabola opening left:the last problem i have is the following
x = -y^2 + 4y - 3
since there is a negative sign in front of the y squared, do i go ahead and factor out a (-1), complete the square, and then plug into the quadratic formula? thanks again for everyone's help! hope you all had a wonderful weekend!