(sorry i dont know how to do the summation symbol)
double summation, j=1 to 4 and k=2 to 8 (j*k)
is there a specific formula you are supposed to use?
Hello,
$\displaystyle \sum_{j=1}^4 \sum_{k=2}^8 jk=\sum_{j=1}^4 \left( \sum_{k=2}^8 jk\right)$
In the second summation, since j doesn't depend on k, you can get it out from the sum :
$\displaystyle =\sum_{j=1}^4 \left(k \sum_{j=1}^8 j\right)$
You can calculate the sum $\displaystyle \sum_{j=1}^8 j$, by using this known formula : $\displaystyle \sum_{k=1}^n k=\frac{n(n+1)}{2}$
And then, you're left with only one sum, that should be easy to compute
Typo alert.....
$\displaystyle \sum_{j=1}^4 \sum_{k=2}^8 jk=\sum_{j=1}^4 \left( \sum_{k=2}^8 jk\right)$
In the second summation, since j doesn't depend on k, you can get it out from the sum :
$\displaystyle =\left(\sum_{j=1}^4 j\right)\left(\sum_{k=2}^8 k\right)$
or
$\displaystyle =\left(\sum_{k=2}^8 k\right)\left(\sum_{j=1}^4 j\right)$