Let y = loga(10) + loga(12) - loga(6)
Find a if y=1
Find a if y=-1
Find a if y=2
If you can show me any of the obove please let me know.
THANKS
Combine the logarithms,
$\displaystyle y=\log_a (10 \cdot 12/6)=\log_a 20$
Thus, by definition of logarithms,
$\displaystyle a^y=20$ (since $\displaystyle a>0$)
Thus, (if $\displaystyle y\not = 0$)
$\displaystyle a=20^{1/y}$
So just substitute the value of "y" to take the value of "a"