Let y = loga(10) + loga(12) - loga(6) Find a if y=1 Find a if y=-1 Find a if y=2 If you can show me any of the obove please let me know. THANKS
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Originally Posted by Mr_Green Let y = loga(10) + loga(12) - loga(6) Find a if y=1 Find a if y=-1 Find a if y=2 If you can show me any of the obove please let me know. THANKS log(10)/log(a) + log(12)/log(a) - log(6)/log(a) = log(20)/log(a) 1 = log(20)/log(a) log(a) = log(20) ln of both sides; a = 20 You do them now; answers, for: y = -1, you should get: a = 1/20 y = 2, you should get: a = 2*sqrt(5)
Originally Posted by Mr_Green Let y = loga(10) + loga(12) - loga(6) Find a if y=1 Find a if y=-1 Find a if y=2 Combine the logarithms, Thus, by definition of logarithms, (since ) Thus, (if ) So just substitute the value of "y" to take the value of "a"
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