am i correct ? not sure would like a little help please. got this sequence an =7-6n/3n+14 i did this: an =-6n/3n + 1/2 an = -12n/6n + 1 an = 1/n + 2 so for large numbers of n, 1/n converges to 0 and so converges to an = 2
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Originally Posted by smartcar29 am i correct ? not sure would like a little help please. got this sequence an =7-6n/3n+14 i did this: an =-6n/3n + 1/2 an = -12n/6n + 1 an = 1/n + 2 so for large numbers of n, 1/n converges to 0 and so converges to an = 2 the nth term of the sequence converges to -2 $\displaystyle \lim_{n \to \infty} \frac{7-6n}{3n+14}$ $\displaystyle \lim_{n \to \infty} \frac{\frac{7}{n} -6}{3+ \frac{14}{n}} = \frac{-6}{3} = -2 $
Originally Posted by smartcar29 i did this: an =-6n/3n + 1/2 You can't break up the denominator because there is a sum there, so this is where your argument fails.
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