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Math Help - Solving Quartics

  1. #1
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    Exclamation Solving Quartics

    Hi

    b^4 - 25b^2 + 37.20 = 0

    Solve for max. height b.

    Could someone please show me how to solve b?
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  2. #2
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    Quote Originally Posted by xwrathbringerx View Post
    Hi

    b^4 - 25b^2 + 37.20 = 0

    Solve for max. height b.

    Could someone please show me how to solve b?
    This is quadratic in form:

    It may help you see it if you let b^2=t \implies b^4=t^2

    So we get

    t^2-25t+37.20=0

    This should get you started.

    Good luck.
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  3. #3
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    Exclamation

    I tried solving it as a quadratic...using b = - \frac{b}{2a} as well as the quadratic formula but it doesn't seem to match the answer, which is 4.84
    Last edited by xwrathbringerx; April 24th 2009 at 09:32 PM.
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  4. #4
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     \frac{-b}{2a} is for finding the axis of symmetry, no need for it here.

     \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} is what you want, a = 1, b = 25, c = 37.20
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