Hi

$\displaystyle b^4 - 25b^2 + 37.20 = 0$

Solve for max. height b.

Could someone please show me how to solve b?

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- Apr 24th 2009, 07:52 PMxwrathbringerxSolving Quartics
Hi

$\displaystyle b^4 - 25b^2 + 37.20 = 0$

Solve for max. height b.

Could someone please show me how to solve b? - Apr 24th 2009, 07:55 PMTheEmptySet
- Apr 24th 2009, 08:02 PMxwrathbringerx
I tried solving it as a quadratic...using b = $\displaystyle - \frac{b}{2a} $ as well as the quadratic formula but it doesn't seem to match the answer, which is 4.84 (Doh)

- Apr 24th 2009, 10:30 PMPeleus
$\displaystyle \frac{-b}{2a} $ is for finding the axis of symmetry, no need for it here.

$\displaystyle \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} $ is what you want, a = 1, b = 25, c = 37.20