# Math Help - Help in polynomial division

1. ## Help in polynomial division

Hello , i am posting anything here for first time.....I am from India, and in XIth Standard presently.

I do have some trouble in division of polynomial by another polynomial but without using long division method and application of formula:
(polynomial in any variable)=(divisor*Q)+remainder; here remainder varies according to degree of polynomial eg. ax+b, ax^2+bx+c, etc.

Suppose a question is to find the remainder with given polynomial: x^3+x^2-3x-2 with divisor x^2+3x+2;

I am not able to do it in short cut method.....Pls if any one have idea aout shorter methods...DO REPLY

2. Originally Posted by findmehere.genius
Hello , i am posting anything here for first time.....I am from India, and in XIth Standard presently.

I do have some trouble in division of polynomial by another polynomial but without using long division method and application of formula:
(polynomial in any variable)=(divisor*Q)+remainder; here remainder varies according to degree of polynomial eg. ax+b, ax^2+bx+c, etc.

Suppose a question is to find the remainder with given polynomial: x^3+x^2-3x-2 with divisor x^2+3x+2;

I am not able to do it in short cut method.....Pls if any one have idea about shorter methods...DO REPLY
This link might help you though I suggest you to practice thoroughly the method you find as easiest. ...

Ruffini's rule - Wikipedia, the free encyclopedia

3. Hi

$x^3+x^2-3x-2 = (x^2+3x+2)P(x) + Q(x)$

$deg(P) = deg(x^3+x^2-3x-2) - deg(x^2+3x+2) = 3 - 2 = 1$
$deg(Q) < deg(x^2+3x+2)$

$x^3+x^2-3x-2 = (x^2+3x+2)(ax+b) + cx+d$

Expand
$x^3+x^2-3x-2= ax^3 + (3a+b)x^2 + (2a+3b+c)x + 2b+d$

Therefore
$a=1$
$3a+b=1$
$2a+3b+c=-3$
$2b+d=-2$

$a=1$
$b=-2$
$c=1$
$d=2$

$x^3+x^2-3x-2 = (x^2+3x+2)(x-2) + x+2$

4. Thanks to both of you who answered my post.
and Ruffini's rule is somewhat very similar to the the complete division method..
actually my teacher said that a polinomial is sum of product of divisor and quotient and of remainder...ok that was clear to me.

He said that in the question we dont have to deal with the quotient so
the polynomial $x^3+x^2-3x-2 = {x^2+3x+2*Q(uotient)}+ax^2+bx+c$ where $ax^2+bx+c$ is remainder.
He said to use the hit and trial method to get a value for x that gives value 0 to the equation $x^2+3x+2$.........such that we put the same value of x in polynomial to be divided and equate the polynomial and remainder........and sorry because I myself am confused in the same......one thing that I can tell that is $ax^2+bx+c$ is remainder and it was solved simultaneously for different value of x.