# Math Help - Exponential equation quicky?

1. ## Exponential equation quicky?

i have the equation below, for which i need to find b and c eventually , with e being the exponential

2(be6c – be4c) = be4c – be2c

thanks

2. ## Missing something?

chose b=0?
c can be anything?

If you arent allowed the trivial solution try substituting $u=e^{2c}$

3. 2(be^6c – be^4c) = be^4c – be^2c

sorry, the original thread is meant to show powers, but it doesnt, hope this helps

I'm meant to get to something in this format, but no idea how
2be^
2c(e^c-1) = be^c(e^c-1)