i have the equation below, for which i need to find b and c eventually , with e being the exponential 2(be6c – be4c) = be4c – be2c I'm really stuck on this... please help thanks
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chose b=0? c can be anything? If you arent allowed the trivial solution try substituting
2(be^6c – be^4c) = be^4c – be^2c sorry, the original thread is meant to show powers, but it doesnt, hope this helps I'm meant to get to something in this format, but no idea how 2be^2c(e^c-1) = be^c(e^c-1)
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