1. ## Help!!!I dun understand the question

Marcus and Bryan decided to visit one another and set off at the same time to each other’s house. The distance between their houses is 7 km. When they met on the road joining their houses, they forgot that they wanted to see each other and continued walking. After they met, it took Bryan nine times as long to reach Marcus’s house as it took Marcus to reach Bryan’s house. What is the distance between Bryan’s house and the point where he met Marcus?

2. You are asked to find out where the two met. (you know the total distance and how far they are away from each others house. That's all you need) And finally how far Bryan is away from his home.

3. ## Dun understand

but i dunnoe the speed

4. Ok look at this:

The distance between their houses is 7 km.
After they met, it took Bryan nine times as long to reach Marcus’s house as it took Marcus to reach Bryan’s house.

That's all you need to find out the position.

$\dfrac{10}{10} = 7000m$

We know that they have met and stand at the same place. In that case:
distance for Bryan to Marcus' House : $\dfrac{9}{10} \cdot 7000 = 6300m$
distance for Marcus to Bryan's House: $\dfrac{1}{10} \cdot 7000 = 700m$

Well now you know the positions!

What is the distance between Bryan’s house and the point where he met Marcus?

If Marcus has to go 700m to reach Bryan's House. Well then the solution is simply 700m.

5. ## thx:)

oo i got this solution, but thought how can it be so easy