Find the Equation of the tangent to the curve of e^2y + xy= 4x + 1,
What I've done so far,
e^2y + xy= 4x + 1
e^2y + xy - 4x - 1 = 0
dy/dx = 2ye^2y + 1 - 4 = 0
dy/dx = 2ye^2y - 3 = 0
I'm not sure if I've done it right because there is no x value, does this mean I sub y=0 into dy/dx instead.
Any help would be appreciated.