Evaluate the SQ root of (2x+1) squared
2x+1 and the exponent 2 are all underneath the radical
My answer = 2x+1 ???
Is this right?
Hi dempc,
You are correct.
You probably should submit a new question in a new post.
Another suggestion. Try to learn a little LATEX to help present you problems a little better. Just click on the code below to see how this one is constructed.
$\displaystyle \sqrt{2}(x+\sqrt{8})=x\sqrt{2}+\sqrt{16}=x\sqrt{2} +4$
The square root of $\displaystyle (2x+ 1)^2$ is |2x+ 1|, which is not necessarily equal to 2x+ 1. For example, if x= -2 then 2x+ 1= 2(-2)+ 1= -3 so $\displaystyle (2x+1)^2= 3^2= 9$. The square root of that is 3, not -3.