Evaluate the SQ root of (2x+1) squared

2x+1 and the exponent 2 are all underneath the radical

Is this right?

2. Originally Posted by dempc
Evaluate the SQ root of (2x+1) squared

2x+1 and the exponent 2 are all underneath the radical

Is this right?
You are correct!

3. Sweet!!.. thanks for checking.. if i have another question pertaining to radicals should i post it under this thread or open a new one?

4. ## another question

The square root of 2 times (x+the sq root of 8)

the sq root of 2 is outside the parenthesis

My answer = x sq root of 2 + 4

5. Originally Posted by dempc
The square root of 2 times (x+the sq root of 8)

the sq root of 2 is outside the parenthesis

My answer = x sq root of 2 + 4
Hi dempc,

You are correct.

You probably should submit a new question in a new post.

Another suggestion. Try to learn a little LATEX to help present you problems a little better. Just click on the code below to see how this one is constructed.

$\displaystyle \sqrt{2}(x+\sqrt{8})=x\sqrt{2}+\sqrt{16}=x\sqrt{2} +4$

6. The square root of $\displaystyle (2x+ 1)^2$ is |2x+ 1|, which is not necessarily equal to 2x+ 1. For example, if x= -2 then 2x+ 1= 2(-2)+ 1= -3 so $\displaystyle (2x+1)^2= 3^2= 9$. The square root of that is 3, not -3.