Results 1 to 3 of 3

Math Help - Simplify as far as possible, sovle the equation, sovle the quadratic equations

  1. #1
    Newbie
    Joined
    Apr 2009
    Posts
    6

    Simplify as far as possible, sovle the equation, sovle the quadratic equations

    Simlify as far as possible

    (i) 10y-5x+7x-3y-x-2y

    (ii) 4(6x-7)-5(2x-3)

    Sovle the equation


    (i) 8x-9 = 4x-21

    (ii) 2(2x-5)=4(2x-1)

    (iii) 5-3x
    ----------- = 5 - x
    4
    Sovle the quadratic equations

    (i) 3x - x - 2 = 0

    (ii) x - 32 - 4x

    I will appreciate if someone can help


    thank you
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Mar 2007
    Posts
    1,240

    Talking

    Quote Originally Posted by Steven777 View Post
    Simlify as far as possible

    (i) 10y-5x+7x-3y-x-2y

    (ii) 4(6x-7)-5(2x-3)
    To learn how to add polynomials and combine "like" terms, try here and here. To learn how to work with parentheses, try here.

    Quote Originally Posted by Steven777 View Post
    Sovle the equation

    (i) 8x-9 = 4x-21

    (ii) 2(2x-5)=4(2x-1)

    (iii) 5-3x
    ----------- = 5 - x
    4
    To learn how to solve linear equations, try here.

    Quote Originally Posted by Steven777 View Post
    Sovle the quadratic equations

    (i) 3x - x - 2 = 0

    (ii) x - 32 - 4x
    To learn how to solve quadratic equations, try here.

    Once you have learned the basic terms and techniques, please attempt at least one exercise from each of the three sets above. If you get stuck, you will then be able to reply with a clear listing of your work and reasoning so far.

    Thank you!
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member
    Joined
    Apr 2008
    Posts
    204
    Quote Originally Posted by Steven777 View Post
    Simplify as far as possible

    (i) 10y-5x+7x-3y-x-2y

    (ii) 4(6x-7)-5(2x-3)
    (i)
    = 10y - 3y - 2y - 5x + 7x - x
    = 5y + x

    (ii)
    = 4 \times 6x - 4 \times 7 - 5 \times 2x - 5 \times -3
    = 24x - 28 - 10x +15
    = 24x - 10x - 28 + 15
    = 14x - 13

    Solve the equation

    (i) 8x-9 = 4x-21

    (ii) 2(2x-5)=4(2x-1)

    (iii) 5-3x
    ----------- = 5 - x
    4
    (i)
    8x - 4x = -21 + 9
    4x = -12
    x = -3

    (ii)
    2 \times 2x + 2 \times -5 = 4 \times 2x + 4 \times -1
    4x -10 = 8x -4
    -10 + 4 = 8x - 4x
    -6 = 4x
    x = -1.5

    (iii) dont understand what you have written for this question


    Solve the quadratic equations

    (i) 3x - x - 2 = 0

    (ii) x - 32 - 4x
    (i)ok the way i was taught to solve these quadratic equations...

    first you write it in the form ax^2 + bx + c, thus for this question, a = 3, b = -1, c = -2.

    Then you work out ac, which is ac = 3 \times -2 = -6.

    Now you have to find two numbers that multiply to give an answer of -6 and add to give an answer of -1 (which is b in this question).

    These two numbers are -3 and 2 ( -3 \times 2 = -6 and -3 + 2 = -1).

    So 3x^2 - x - 2 = 0 can be rewritten as:
    3x^2 - 3x + 2x - 2 = 0
    3x(x - 1) + 2(x - 1) = 0
    (3x + 2) (x - 1) = 0

    This means that either 3x + 2 or x - 1 have to be equal to 0 (or both)

    Therefore,
    3x + 2 = 0
    3x = -2
    x = -\frac{2}{3}

    OR

    x - 1 = 0
    x = 1


    (ii) have a go at this one by yourself now that I have shown you how to solve quadratic equations
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 2
    Last Post: February 21st 2011, 01:37 PM
  2. sovle inequality
    Posted in the Algebra Forum
    Replies: 2
    Last Post: November 3rd 2008, 04:32 PM
  3. sovle for x, use identity
    Posted in the Trigonometry Forum
    Replies: 3
    Last Post: August 16th 2008, 01:58 PM
  4. sovle equation
    Posted in the Algebra Forum
    Replies: 1
    Last Post: April 14th 2008, 11:08 AM
  5. Sovle for x
    Posted in the Algebra Forum
    Replies: 2
    Last Post: January 16th 2008, 05:34 PM

Search Tags


/mathhelpforum @mathhelpforum