solve the exponential function: 4(2^x) + 31(2^x) - 8 = 0
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Originally Posted by math123456 solve the exponential function: 4(2^x) + 31(2^x) - 8 = 0 It simplifies to $\displaystyle 2^x = \frac{8}{35}$. Solve this.
How do you solve for x: 2^x = 8/35
Originally Posted by math123456 solve for x: 2^x = 8/35 Take logs: $\displaystyle x \log(2)=\log(8/35)$ and solve. CB
how would you answer that in exact form
Originally Posted by CaptainBlack Take logs: $\displaystyle x \log(2)=\log(8/35)$ and solve. CB Originally Posted by math123456 how would you answer that in exact form Divide through by log(2) to isolate it. The exact form will have log terms in it:
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