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Math Help - Solving an exponential equation question 2

  1. #1
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    Exclamation Solving an exponential equation question 2

    solve the exponential function:

    4(2^x) + 31(2^x) - 8 = 0
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  2. #2
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    Quote Originally Posted by math123456 View Post
    solve the exponential function:

    4(2^x) + 31(2^x) - 8 = 0
    It simplifies to 2^x = \frac{8}{35}. Solve this.
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  3. #3
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    Exclamation Solving an exponential equation question 2

    How do you solve for x:

    2^x = 8/35
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  4. #4
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    Quote Originally Posted by math123456 View Post
    solve for x:

    2^x = 8/35
    Take logs:

    x \log(2)=\log(8/35)

    and solve.

    CB
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  5. #5
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    Exclamation

    how would you answer that in exact form
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  6. #6
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    Quote Originally Posted by CaptainBlack View Post
    Take logs:

    x \log(2)=\log(8/35)

    and solve.

    CB
    Quote Originally Posted by math123456 View Post
    how would you answer that in exact form
    Divide through by log(2) to isolate it. The exact form will have log terms in it:
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