-3.6>0.6x 15e-3<20e+12
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Originally Posted by jerryramos -3.6>0.6x 15e-3<20e+12 The solution to the first statement is $\displaystyle 0.6x < -3.6$ $\displaystyle \frac{0.6x}{0.6} < \frac{-3.6}{0.6}$ $\displaystyle x < -0.06$ The second statement is true, but why are you stating it? -Dan
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