Solve by using square root principle
[ (x+1)/2 ]^2 - (x/2) = 2
Answer key: ±√7
I tried the following:
[ (x+1)/2 ]^2 - (x/2) = 2
(x^2/4) + (1/4) - (x/2) = 2
-bring the (1/4) to RHS
(x^2/4) - (x/2) = (7/4)
-LCD 4
x^2 - 2x = 7
I'm stuck now as I have a middle term (-2x), otherwise the square root principle would work out nice. How to solve this using the square root principle?
Thanks.
Thanks!
This part is confusing:
[ (x/2) + (1/2) ]^2
I worked it out as:
(x^2/4) + (x/4) + (x/4) + (1/4)
Add (x/4) with (x/4), this gives me (2x/4):
(x^2/4) + (2x/4) + (1/4)
Simplify (2x/4) by dividing by 2, this gives me (x/2):
(x^2/4) + (x/2) + (1/4)
Are the above workings right? Is that how I expand the binomial fraction?
Thanks.