I need to find the product:

(1-1/2)(1-1/3)(1-1/4)(1-1/5)......(1-1/499)(1-1/500) =

NOTICE: The list goes from (1-1/2) all the way to

(1 - 1/500).

How do I solve this question?

How do I find the product?

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- Apr 20th 2009, 04:38 AMmagentaritaFind the Product
I need to find the product:

(1-1/2)(1-1/3)(1-1/4)(1-1/5)......(1-1/499)(1-1/500) =

NOTICE: The list goes from (1-1/2) all the way to

(1 - 1/500).

How do I solve this question?

How do I find the product?

- Apr 20th 2009, 04:49 AMADARSH
- Apr 20th 2009, 05:39 AMe^(i*pi)
- Apr 20th 2009, 09:01 PMmagentaritatell me
- Apr 20th 2009, 09:02 PMmagentaritatell me...
- Apr 20th 2009, 10:03 PMADARSH
Your formula is not correct

http://www.mathhelpforum.com/math-he...7000fa16-1.gif

$\displaystyle =\frac{(500-1)(500-2).....(2)(1)}{(500)(499)...(2)(1)}$

$\displaystyle =\frac{(500-1)!}{500!}$

$\displaystyle =\frac{(499)!}{500!}$

Remember that (n-1)! is not equal to (1-n)!

$\displaystyle =\frac{(n-1)!}{n!} = \frac{1}{n} {\color{red}\ne} \frac{(1-n)!}{n!}$

$\displaystyle =\frac{1}{500}$ - Apr 21st 2009, 09:01 PMmagentaritaI see...