$\displaystyle \frac{8}{y-2}-\frac{13}{2}=\frac{3}{2y-4}$

LCD must be 2y-4

$\displaystyle (\frac{8}{y-2})(\frac{2y-4}{2y-4})-(\frac{13}{2})(\frac{2y-4}{2y-4})=(\frac{3}{2y-4})(\frac{2y-4}{2y-4})$

then

(16y-32)-(26y-52)=6y-12

16y-32-26y+52=6y-12

-16y=-32

y=2

Someplace I've must made a mistake as my book says y=3. Somebody?

Thanks