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Math Help - Solving Radical Equations

  1. #1
    Newbie stmsnyder1's Avatar
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    Solving Radical Equations

    Hi,

    I can't solve this radical equation, can someone help?

    8√x+3 =11

    Incase someone has a hard time reading that, because I know, sometimes I do, it says eight, cube root, x+3=11. The x+3 is inside the cube root, but the 11 is not.

    x=4, but I don't know how the person who told me got it.

    Thanks-
    Isabel
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  2. #2
    MHF Contributor
    Joined
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    Talking

    Quote Originally Posted by stmsnyder1 View Post
    I can't solve this radical equation, can someone help?

    8√x+3 =11
    So the equation, in text form, is 8*cbrt[x + 3] = 11 or, in LaTeX formatting:

    . . . . . 8\,\sqrt[3]{x\, +\, 3}\, =\, 11

    A good first step in solving this radical equation would be to get the radical by itself, so start by dividing through by 8.

    Then cube both sides to get:

    . . . . . x\, +\, 3\, =\, \frac{1331}{512}

    Subtract the 3 to the right-hand side, and simplify.

    By the way, whoever told you that the solution is "x = 4" was mistaken. That's why, when you plugged "4" in for "x" on the left-hand side, you did not get a value of 11.
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