Solve the system of linear equations algebraically.
I tried to do this many times using various different ways, but I could never get the answer. Help?
I also attached a picture of the original problem for reference.
Since we cannot see your steps, it will not be possible to find any errors. Sorry!
What methods are you allowed to use? For instance, can you plug this into your graphing calculator? Can you use Cramer's Rule, with your calculator computing the determinants?
Thank you!
Hello, chrozer!
We can do it by Elimination . . . but it takes longer and is quite messy.
I hate those subscripts; I'll change the variables.
And I'll multiply the third equation by -1.
Solve the system of linear equations algebraically.
. . and we have: .
. . and we have: .
Add [E6] and [E7]: .
Substitute into [E6]: .
Substitute into [E1], [E2], [E3]:
. .
And we have: .
Substitute into (E10): .
Substitute into (E8): .
Therefore: .